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MHT CET Medical202621 April 2026Evening ShiftChemistryAminesActual

Aniline undergoes diazotization with NaNO ₂ /HCl to give compound A. Compound A reacts with fluoroboric acid to give compound B. When B is heated with aq. NaNO ₂ in the presence of copper, it forms compound C. Identify C.

Options

  1. AAr - F
  2. BAr - Cl
  3. CAr - H
  4. DAr - NO ₂

Correct answer

D. Ar - NO ₂

Step-by-step solution

Aniline reacts with NaNO ₂ and HCl at 0-5^ C to undergo diazotization, forming benzenediazonium chloride (Compound A). Ar - NH ₂ NaNO ₂/ HCl Ar - N ₂^+ Cl ^- (A) Benzenediazonium chloride reacts with fluoroboric acid ( HBF ₄ ) to yield benzenediazonium fluoroborate (Compound B). Ar - N ₂^+ Cl ^- HBF ₄ Ar - N ₂^+ BF ₄^- (B) When benzenediazonium fluoroborate is heated with aqueous NaNO ₂ in the presence of copper, the diazonium group is replaced by a nitro group, forming nitrobenzene (Compound C). Ar - N ₂^+ BF ₄^-

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