MHT CET Medical202626 April 2026Morning ShiftChemistryElectrochemistryActual
Calculate the conductivity of 0.025 M BaCl ₂ solution if the molar conductivity of salt at 25^ C is 325 ⁻¹ cm ^2 mol ⁻¹ .
Options
- A8.125 10⁻² ⁻¹ cm ⁻¹
- B8.125 10⁻³ ⁻¹ cm ⁻¹
- C7.6923 10⁻² ⁻¹ cm ⁻¹
- D8.372 10⁻² ⁻¹ cm ⁻¹
Correct answer
B. 8.125 10⁻³ ⁻¹ cm ⁻¹
Step-by-step solution
Given: Concentration, C = 0.025 M Molar conductivity, _m = 325 ⁻¹ cm ^2 mol ⁻¹ The relationship between molar conductivity and conductivity ( ) is given by: _m = 1000 C Rearranging the formula to solve for : = _m C 1000 Substituting the given values: = 325 0.025 1000 = 8.125 1000 = 8.125 10⁻³ ⁻¹ cm ⁻¹ Answer: 8.125 10⁻³ ⁻¹ cm ⁻¹