Calculate the time required in second to deposit 5.85 g Ni from NiCl ₂ solution by passing 10 A current (molar mass of Ni = 58.5 g mol ⁻¹ )

Step-by-step solution

The reaction for the deposition of Ni is: Ni ²⁺ + 2e⁻ Ni Number of moles of Ni deposited = 5.85 58.5 = 0.1 mol Since 1 mole of Ni requires 2 moles of electrons, the total charge required is: Q = 0.1 2 96500 = 19300 C Using the formula Q = I t : 19300 = 10 t t = 1930 s Answer: 1930