How long (in minutes) must a 2\ A current be passed through AgNO_3 solution to deposit 5.4\ g Ag ? [Molar mass of Ag = 108\ g mol^ -1 ]

Question

Quantrex Academy · Accepted Answer

Correct answer: A. 40.2\ .

According to Faraday's first law of electrolysis:

m = \dfrac{E \times I \times t}{96500}

Here,

m = 5.4\ \text{g}

,

I = 2\ \text{A}

, and equivalent weight of Ag,

E = \dfrac{108}{1} = 108\ \text{g eq}^{-1}

.

Substituting the values:

5.4 = \dfrac{108 \times 2 \times t}{96500}

t = \dfrac{5.4 \times 96500}{108 \times 2}

t = 2412.5\ \text{s}

Converting time into minutes:

t = \dfrac{2412.5}{60}\ \text\min \approx 40.2\ \text\min

Answer:

40.2\ \text\min

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How long (in minutes) must a 2\ A current be passed through AgNO_3...