Solubility of MA ₂ type of electrolyte is 0.5 10⁻⁴ mol/litre . Then find out k_ sp of electrolyte?

Step-by-step solution

The dissociation of the electrolyte MA ₂ is given by: MA ₂ M ²⁺ + 2 A ⁻ Let the solubility of the electrolyte be s . Then the concentrations of the ions are: [ M ²⁺] = s [ A ⁻] = 2s The solubility product K_ sp is: K_ sp = [ M ²⁺][ A ⁻]^2 K_ sp = (s)(2s)^2 = 4s^3 Given s = 0.5 10⁻⁴ mol/L = 5 10⁻⁵ mol/L , substituting this value: K_ sp = 4 (5 10⁻⁵)^3 K_ sp = 4 125 10⁻¹⁵ K_ sp = 500 10⁻¹⁵ = 5 10⁻¹³ Answer: 5 10⁻¹³