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MHT CET 202624 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
24 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Ionic Equilibrium

MHT CET 2026 · 24 April · Morning Shift · Chemistry · Ionic Equilibrium

Calculate the amount of NaOH in g/L in a one L solution of it with...

Calculate the amount of NaOH in g/L in a one L solution of it with the pH of 12. (Molar mass of NaOH=40\text{NaOH}=40 g/mol)

Options

  1. A0.40.4 g/L
  2. B22 g/L
  3. C44 g/L
  4. D0.20.2 g/L

Correct answer

A. 0.40.4 g/L

Step-by-step solution

Given pH=12\text{pH} = 12

pOH=14−pH=14−12=2\text{pOH} = 14 - \text{pH} = 14 - 12 = 2

[OH−]=10−pOH=10−2 M=0.01 M[\text{OH}^{-}] = 10^{-\text{pOH}} = 10^{-2} \text{ M} = 0.01 \text{ M}

Since NaOH\text{NaOH} is a strong base, it dissociates completely.

[NaOH]=[OH−]=0.01 M[\text{NaOH}] = [\text{OH}^{-}] = 0.01 \text{ M}

Amount of NaOH\text{NaOH} in g/L =Molarity×Molar mass= \text{Molarity} \times \text{Molar mass}

Amount =0.01 mol/L×40 g/mol=0.4 g/L= 0.01 \text{ mol/L} \times 40 \text{ g/mol} = 0.4 \text{ g/L}

Answer: 0.40.4 g/L
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