What is pH of HCl solution containing 0.365 g of HCl in 100 mL of solution, assuming complete dissociation at 298 K? ( Molar mass of HCl = 36.5 g/mol)

Step-by-step solution

Number of moles of HCl = Mass Molar mass = 0.365 36.5 = 0.01 mol Volume of solution = 100 mL = 0.1 L Molarity of HCl = Moles Volume in L = 0.01 0.1 = 0.1 M Since HCl is a strong acid, it dissociates completely. [ H ⁺] = 0.1 M = 10⁻¹ M pH = - [ H ⁺] = - (10⁻¹) = 1 Answer: 1