Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET Medical202621 April 2026Evening ShiftChemistryIonic EquilibriumActual

Calculate the pH of the resulting solution obtained by mixing 60 mL 0.1 M HCl and 40 mL 0.1 M NaOH.

Options

  1. A2.301
  2. B1.699
  3. C2.699
  4. D3.301

Correct answer

B. 1.699

Step-by-step solution

Millimoles of HCl = 60 0.1 = 6 mmol Millimoles of NaOH = 40 0.1 = 4 mmol Since HCl and NaOH react in a 1:1 ratio, the remaining millimoles of HCl = 6 - 4 = 2 mmol . Total volume of the mixture = 60 + 40 = 100 mL . Concentration of H ⁺ ions in the resulting solution is given by: [ H ⁺] = 2 mmol 100 mL = 0.02 M pH = - [ H ⁺] = - (2 10⁻²) pH = 2 - 2 = 2 - 0.301 = 1.699 Answer: 1.699

Practice Ionic Equilibrium on Quantrex Academy →

More from Ionic Equilibrium

What amount of NaOH should be dissolved in a 500 mL solution, so that the p ^ H of solution is 12 at 298 K ? 2026Which of the following buffer solutions is used for precipitation of cations of the III A group? 2026The degree of dissociation of weak acid is directly proportional to 2026Which from the following is Lewis base? 2026The solubility of Fe(OH) ₃ is x mole per liter. Find its K_ sp . 2026The Basic buffer solution is made with 0.1 M NH ₄ OH and 0.2 M NH ₄ Cl . If K_b for the base is 1.8 10⁻⁵ , what is the pH of the buffer? 2026The hydrogen ion concentration of the ocean is about 2 10⁻⁹ M . What is the pOH of ocean? 2026Calculate the dissociation constant of a weak monobasic acid if it is 0.04% dissociated in a 0.01M solution. 2026 Full Ionic Equilibrium list All MHT CET Medical PYQs