The degree of dissociation of a monobasic acid in its 0.1M solution at 300 K is 1.342 10⁻² . Calculate the degree of dissociation of the same acid in its 0.02M solution.

Step-by-step solution

Using Ostwald's dilution law for a weak monobasic acid: K_a = C ^2 For the first solution, C₁ = 0.1 M and ₁ = 1.342 10⁻² : K_a = 0.1 (1.342 10⁻²)^2 = 0.1 1.8 10⁻⁴ = 1.8 10⁻⁵ For the second solution, C₂ = 0.02 M: K_a = C₂ ₂^2 1.8 10⁻⁵ = 0.02 ₂^2 ₂^2 = 1.8 10⁻⁵ 0.02 = 9 10⁻⁴ ₂ = 3.0 10⁻² Answer: 3.0 10⁻²