Calculate the pressure at which solubility of a certain gas in water is 0.165 mol L ⁻¹ at 25 ^ C. (Henry's law constant for this gas in water is 0.034 mol L ⁻¹ bar ⁻¹ at 25 ^ C.)

Step-by-step solution

According to Henry's law, the solubility of a gas in a liquid is given by: S = K_ H P Given: S = 0.165 mol L ⁻¹ K_ H = 0.034 mol L ⁻¹ bar ⁻¹ Substituting the values: 0.165 = 0.034 P P = 0.165 0.034 P = 4.85 bar Answer: 4.85 bar