If the r.m.s. current in an a.c. circuit is 5 A, having frequency 50 Hz. The value of current 1 300 s after its value becomes zero (in A) is ( /3) = (3)^ 0.5 /2

Step-by-step solution

The equation for alternating current is given by I = I₀ ( t) . Given I_ rms = 5 A, the peak current is: I₀ = I_ rms 2 = 5 2 A The angular frequency is: = 2 f = 2 50 = 100 rad/s Substituting t = 1 300 s into the current equation: I = 5 2 (100 1 300 ) I = 5 2 ( 3 ) I = 5 2 3 2 I = 5 3 2 A Answer: 5 3 2