At resonance, the LC parallel resonant circuit

For a parallel LC circuit, the admittance is given by Y = \dfrac{1}{j \omega L} + j \omega C = j \left( \omega C - \dfrac{1}{\omega L}\right).At resonance, the inductive reactance equals the capacitive reactance, which means \omega C = $\dfrac{1}{\omega L}$.Substituting this into the admittance equation gives $Y = 0$.Since impedance $Z = \dfrac{1}{Y}$, the impedance approaches infinity as the admittance approaches zero.Therefore, at resonance, an LC parallel resonant circuit has a very high impedance.Answer: has a very high impedance.