MHT CET Medical202623 April 2026Evening ShiftPhysicsDual Nature of MatterActual
Light of frequency 4 ₀ is incident on the metal of threshold frequency ₀ . The maximum kinetic energy of the emitted photoelectron is ( h = Planck's constant)
Options
- A3h ₀
- B2h ₀
- C3 2 h ₀
- D1 2 h ₀
Correct answer
A. 3h ₀
Step-by-step solution
According to Einstein's photoelectric equation, the maximum kinetic energy of the emitted photoelectron is given by K_ max = h - h ₀ Given that the frequency of incident light is = 4 ₀ and the threshold frequency is ₀ . Substituting the values, we get K_ max = h(4 ₀) - h ₀ K_ max = 3h ₀ Answer: 3h ₀