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MHT CET Medical202622 April 2026Morning ShiftPhysicsDual Nature of MatterActual

Let E_e and E_p represent kinetic energy of electron and photon respectively. If de-Broglie wavelength _p of a photon is four times the de-Broglie wavelenght _e of an electron, the E_p E_e is [ speed of electron = C 100 , C = velocity of light]

Options

  1. A1 100
  2. B1 50
  3. C50
  4. D100

Correct answer

C. 50

Step-by-step solution

The kinetic energy of a photon is given by: E_p = hc _p The kinetic energy of an electron can be written in terms of its de-Broglie wavelength _e and velocity v : E_e = 1 2 m v^2 = 1 2 (mv) v = 1 2 ( h _e ) v Taking the ratio of the kinetic energies: E_p E_e = hc _p hv 2 _e = 2c v _e _p Given that v = c 100 and _p = 4 _e , we substitute these values into the ratio: E_p E_e = 2c ( c 100 ) _e 4 _e E_p E_e = 200 1 4 = 50 Answer: 50

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