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MHT CET Medical202624 April 2026Evening ShiftPhysicsElectrostaticsActual

Three point charges q₁ = 1 C , q₂ = -2 C , and q₃ = 3 C are placed at (1, 0, 0) , (0, 2, 0) and (0, 0, 3) respectively. The electric potential at origin is 1 4 ₀ = 9 10^9 SI unit

Options

  1. A10^6 V
  2. B3 10^3 V
  3. C6 10^6 V
  4. D9 10^3 V

Correct answer

D. 9 10^3 V

Step-by-step solution

The electric potential at the origin is given by the superposition principle: V = 1 4 ₀ ( q₁ r₁ + q₂ r₂ + q₃ r₃ ) The distances of the charges from the origin are: r₁ = 1^2 + 0^2 + 0^2 = 1 m r₂ = 0^2 + 2^2 + 0^2 = 2 m r₃ = 0^2 + 0^2 + 3^2 = 3 m Substituting the values of charges and distances: V = 9 10^9 ( 1 10⁻⁶ 1 + -2 10⁻⁶ 2 + 3 10⁻⁶ 3 ) V = 9 10^9 10⁻⁶ (1 - 1 + 1) V = 9 10^3 V Answer: 9 10^3 V

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