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MHT CET 202621 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
21 April
Shift
Morning Shift
Subject
Physics
Chapter
Kinetic Theory of Gases

MHT CET 2026 · 21 April · Morning Shift · Physics · Kinetic Theory of Gases

C_p and C_v are the specific heats at constant pressure and...

CpC_p and CvC_v are the specific heats at constant pressure and constant volume respectively. It is observed that Cp−Cv=aC_p - C_v = a for hydrogen gas and Cp−Cv=bC_p - C_v = b for carbon dioxide gas. The correct relationship between ' a' and 'b' is ( atomic weight of hydrogen , carbon and oxygen are 1u, 12 u and 16 u respectively)

Options

  1. Aa=ba = b
  2. Ba=22 ba = 22\ b
  3. Ca=44 ba = 44\ b
  4. Da=114ba = \dfrac{1}{14b}

Correct answer

B. a=22 ba = 22\ b

Step-by-step solution

For a given gas, the molar heat capacities at constant pressure and constant volume are related by Mayer's relation:

CP,m−CV,m=RC_{P,m} - C_{V,m} = R

The specific heat is defined as the heat capacity per unit mass. Therefore, the difference between the specific heats at constant pressure (CpC_p) and constant volume (CvC_v) is given by:

Cp−Cv=RMC_p - C_v = \dfrac{R}{M}

where MM is the molar mass of the gas.

For hydrogen gas (H2H_2), the molar mass is MH2=2×1=2M_{H_2} = 2 \times 1 = 2 u. Thus:

a=R2a = \dfrac{R}{2}

For carbon dioxide gas (CO2CO_2), the molar mass is MCO2=12+2×16=44M_{CO_2} = 12 + 2 \times 16 = 44 u. Thus:

b=R44b = \dfrac{R}{44}

Taking the ratio of aa to bb:

ab=R2R44=442=22\dfrac{a}{b} = \dfrac{\dfrac{R}{2}}{\dfrac{R}{44}} = \dfrac{44}{2} = 22

⇒a=22b\Rightarrow a = 22 b

Answer: a=22 ba = 22\ b
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