The heat generated in a circuit is given by Q = I^2 R t . If the percentage error in the measurement of Q is 1 % , R is 2 % , and t is 1 % , then the percentage error in the measurement of current I is

Step-by-step solution

Given Q = I^2 R t Rearranging the formula for I , we get: I = ( Q R t )^ 1/2 The maximum percentage error in I is given by: I I 100 = 1 2 ( Q Q 100 ) + 1 2 ( R R 100 ) + 1 2 ( t t 100 ) Substituting the given percentage errors: I I 100 = 1 2 (1 %) + 1 2 (2 %) + 1 2 (1 %) I I 100 = 0.5 % + 1 % + 0.5 % = 2 % Answer: 2 %