The physical quantity P= a³b² c^ 1/3 d^ 1/4 , where the percentage error in a, b, c, and d are 1 % , 3 2 % , 3 % , and 2 % respectively. Then the percentage error in P is

Step-by-step solution

Given P = a³b² c^ 1/3 d^ 1/4 The maximum percentage error in P is given by: P P 100 = 3 ( a a 100 ) + 2 ( b b 100 ) + 1 3 ( c c 100 ) + 1 4 ( d d 100 ) Substituting the given percentage errors: P P 100 = 3(1 %) + 2 ( 3 2 % ) + 1 3 (3 %) + 1 4 (2 %) P P 100 = 3 % + 3 % + 1 % + 0.5 % = 7.5 % Answer: 7.5 %