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MHT CET 202622 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
22 April
Shift
Morning Shift
Subject
Physics
Chapter
Motion in One Dimension

MHT CET 2026 · 22 April · Morning Shift · Physics · Motion in One Dimension

A vehicle runs on a straight road of length 'L'. It travels half...

A vehicle runs on a straight road of length 'L'. It travels half the distance with speed V and the remaining distance with speed \dfrac{3V}{2}$. Its average speed is

Options

  1. A4V3\dfrac{4V}{3}
  2. B3V4\dfrac{3V}{4}
  3. C5V6\dfrac{5V}{6}
  4. D6V5\dfrac{6V}{5}

Correct answer

D. 6V5\dfrac{6V}{5}

Step-by-step solution

Total distance is LL.

Time taken to travel the first half distance is t1=L/2V=L2Vt_1 = \dfrac{L/2}{V} = \dfrac{L}{2V}.

Time taken to travel the second half distance is t2=L/23V/2=L3Vt_2 = \dfrac{L/2}{3V/2} = \dfrac{L}{3V}.

Total time taken is t=t1+t2=L2V+L3V=5L6Vt = t_1 + t_2 = \dfrac{L}{2V} + \dfrac{L}{3V} = \dfrac{5L}{6V}.

Average speed is vavg=Total distanceTotal time=L5L6V=6V5v_{avg} = \dfrac{\text{Total distance}}{\text{Total time}} = \dfrac{L}{\dfrac{5L}{6V}} = \dfrac{6V}{5}.

Answer: 6V5\dfrac{6V}{5}
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