Two cars, P and Q move toward each other, getting 8 m closer every second. If they move in the same direction, they get 0.6 m closer every second. If car P is faster than car Q then, the ratio of speeds of car P to car Q is

Step-by-step solution

Let the speeds of car P and car Q be v_P and v_Q respectively, and v_P > v_Q . When the cars move towards each other, their relative speed is the sum of their individual speeds. Since they get 8 m closer every second: v_P + v_Q = 8 When the cars move in the same direction, their relative speed is the difference of their individual speeds. Since they get 0.6 m closer every second: v_P - v_Q = 0.6 Adding the two equations, we get: 2v_P = 8.6 v_P = 4.3 m/s Subtracting the second equation from the first, we get: 2v_Q =