Consider the following nuclear fission reaction
${}_0^1 n + {}_{92}^{235}U \rightarrow {}_Z^A Y + {}_{41}^{99}Nb + neutrons$ .
If $4$ neutrons are released during the fission process, then $A$ and $Z$ are

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Consider the following nuclear fission reaction _0^1 n + _ 92 ^ 235 U arrow _Z^A Y + _ 41 ^ 99 Nb + neutrons . If 4 neutrons are released during the fission process, then A and Z are

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Correct answer: A. A = 133 and Z = 51

The nuclear reaction is given by: _0^1 n + _ 92 ^ 235 U arrow _Z^A Y + _ 41 ^ 99 Nb + 4 _0^1 n Applying the principle of conservation of mass number: 1 + 235 = A + 99 + 4(1) 236 = A + 103 A = 133 Applying the principle of conservation of atomic number: 0 + 92 = Z + 41 + 4(0) 92 = Z + 41 Z = 51 Thus, A = 133 and Z = 51 . Answer: A = 133 and Z = 51

Consider the following nuclear fission reaction _0^1 n + _ 92 ^ 235...

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