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Consider the following nuclear fission reaction ₀^1 n + ₉₂²³⁵U _Z^A Y + ₄₁⁹⁹Nb + neutrons . If 4 neutrons are released during the fission process, then A and Z are

Options

  1. AA = 133 and Z = 51
  2. BA = 51 and Z = 133
  3. CA = 339 and Z = 133
  4. DA = 133 and Z = 339

Correct answer

A. A = 133 and Z = 51

Step-by-step solution

The nuclear reaction is given by: ₀^1 n + ₉₂²³⁵U _Z^A Y + ₄₁⁹⁹Nb + 4 ₀^1 n Applying the principle of conservation of mass number: 1 + 235 = A + 99 + 4(1) 236 = A + 103 A = 133 Applying the principle of conservation of atomic number: 0 + 92 = Z + 41 + 4(0) 92 = Z + 41 Z = 51 Thus, A = 133 and Z = 51 . Answer: A = 133 and Z = 51

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