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MHT CET 202625 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
25 April
Shift
Morning Shift
Subject
Physics
Chapter
Oscillations

MHT CET 2026 · 25 April · Morning Shift · Physics · Oscillations

Identify the equation that DOES NOT represent oscillatory motion....

Identify the equation that DOES NOT represent oscillatory motion.
(Aisamplitudeofmotion)is amplitude of motion)

Options

  1. Ay=Asin⁡ωt+Acos⁡2ωty = A\sin\omega t + A\cos 2\omega t
  2. Bx=Acos⁡(\omegat−π4)x = A\cos \left(\omegat - \dfrac{\pi}{4}\right)
  3. Cy=Asin⁡ωt+Acos⁡(ωt+π/2)y = A\sin\omega t + A\cos(\omega t + \pi/2)
  4. Dy=Asin⁡(\omegat−π4)y = A\sin \left(\omegat - \dfrac{\pi}{4}\right)

Correct answer

C. y=Asin⁡ωt+Acos⁡(ωt+π/2)y = A\sin\omega t + A\cos(\omega t + \pi/2)

Step-by-step solution

Let us analyze each option to determine if it represents oscillatory motion.

For the equation y=Asin⁡ωt+Acos⁡2ωty = A\sin\omega t + A\cos 2\omega t, the motion is a superposition of two harmonic functions with commensurable frequencies. This represents a periodic and oscillatory motion.

For the equation x = A\cos \left(\omegat - \dfrac{\pi}{4}\right), the motion is simple harmonic, which is inherently oscillatory.

For the equationy = A\sinω\omegat + A\cos(ω\omegat + π\pi/2),wecansimplifyitusingthetrigonometricidentity, we can simplify it using the trigonometric identity\cos(θ+π\theta + \pi/2) = -\sinθ:<br>\theta:<br>y = A\sinω\omegat - A\sinω\omegat = 0<br>Sincethedisplacement<br>Since the displacementyiszeroforalltimeis zero for all timet,theparticleremainsatrestattheorigin.Therefore,thisdoesnotrepresentoscillatorymotion.<br><br>Fortheequation, the particle remains at rest at the origin. Therefore, this does not represent oscillatory motion.<br><br>For the equationy = A\sin \left(\omega t - \dfrac{\pi}{4}\right),themotionissimpleharmonic,whichisoscillatory.<br><br>Thus,theequationthatdoesnotrepresentoscillatorymotionis, the motion is simple harmonic, which is oscillatory.<br><br>Thus, the equation that does not represent oscillatory motion isy = A\sin\omega t + A\cos(\omega t + \pi/2).<br><br>Answer:.<br><br>Answer:y = A\sin\omega t + A\cos(\omega t + \pi/2)
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