The graph shows variation of displacement of a particle performing SHM with time t. which of the following statements is correct from the graph?

Step-by-step solution

From the given graph, the displacement of the particle is x = A ( t) , where = 2 T . At t = T , displacement x = 0 . Acceleration a = - ^2 x = 0 . Thus, acceleration is zero. At t = 3T 4 , displacement x = -A (extreme position). The restoring force is F = -kx . The magnitude of force is |F| = k|-A| = kA , which is the maximum value. Thus, the force is maximum. At t = T 2 , displacement x = 0 (mean position). Velocity is maximum at the mean position, not zero. At t = T 4 , displacement x = A (extreme position). Velo