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MHT CET 202622 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
22 April
Shift
Morning Shift
Subject
Physics
Chapter
Ray Optics

MHT CET 2026 · 22 April · Morning Shift · Physics · Ray Optics

A convex lens of focal length 'f' produces a real image whose size...

A convex lens of focal length 'f' produces a real image whose size is 'm' times the size of an object. The distance of the image from the lens, 'v', is given by

Options

  1. Af(1−m)f(1-m)
  2. Bf/(m+1)f / (m+1)
  3. Cf(m−1)f(m-1)
  4. Df(m+1)f(m+1)

Correct answer

D. f(m+1)f(m+1)

Step-by-step solution

For a convex lens forming a real image, the magnification is negative.

M=vu=−mM = \dfrac{v}{u} = -m

u=−vmu = -\dfrac{v}{m}

Using the lens formula:

1v−1u=1f\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}

Substituting the value of uu:

1v−(−mv)=1f\dfrac{1}{v} - \left(-\dfrac{m}{v}\right) = \dfrac{1}{f}

1v+mv=1f\dfrac{1}{v} + \dfrac{m}{v} = \dfrac{1}{f}

1+mv=1f\dfrac{1+m}{v} = \dfrac{1}{f}

v=f(m+1)v = f(m+1)

Answer: f(m+1)f(m+1)
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