MHT CET Medical202621 April 2026Evening ShiftPhysicsThermodynamicsActual
Thermodynamic change in the system from state (P₁, V₁) to (P₂, V₂) is shown in the figure. The work done by the system is
Options
- A16 10^5 J
- B12 10^5 J
- C8 10^5 J
- D4 10^5 J
Correct answer
C. 8 10^5 J
Step-by-step solution
The work done by the system during a thermodynamic process is equal to the area under the P-V graph projected on the volume axis. From the given graph, the process from state A to state D forms a trapezium with the volume axis. The initial state A has coordinates P₁ = 1 10^5 N/m ^2 and V₁ = 1 m ^3 . The final state D has coordinates P₂ = 3 10^5 N/m ^2 and V₂ = 5 m ^3 . The work done W is the area of this trapezium: W = 1 2 (P₁ + P₂) (V₂ - V₁) Substituting the values: W = 1 2 (1 10^5 + 3 10^5) (5 - 1) W = 1 2 (4 10^