A gas is taken through a cycle A B C A , as shown in the figure. The net work done by the gas is

Step-by-step solution

The net work done by the gas in a cyclic process is equal to the area enclosed by the cycle on the P-V diagram. From the given graph, the cycle A B C A forms a right-angled triangle. The base of the triangle is V = (6 - 2) 10⁻³ m ^3 = 4 10⁻³ m ^3 . The height of the triangle is P = (6 - 3) 10^5 Pa = 3 10^5 Pa . Since the cycle is clockwise, the net work done is positive. Net work done (W) = Area of ABC W = 1 2 base height W = 1 2 (4 10⁻³ m ^3) (3 10^5 Pa ) W = 1 2 12 10^2 J W = 600 J Answer: 600 J