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The equation of two interfering light waves are y₁ = b t and y₂ = b ( t + ) . If the light waves interfere destructively, then the possible value of are

Options

  1. A3 2 , 5 2 , 13 2 ,
  2. B3 2 , 7 2 , 13 2 ,
  3. C3 2 , 7 2 , 11 2 ,
  4. D3 2 , 9 2 , 11 2 ,

Correct answer

C. 3 2 , 7 2 , 11 2 ,

Step-by-step solution

The given equations of the light waves are: y₁ = b t = b ( t + 2 ) y₂ = b ( t + ) The phase difference between the two waves is: = ( t + ) - ( t + 2 ) = - 2 For destructive interference, the phase difference must be an odd multiple of : = (2n - 1) - 2 = (2n - 1) = (2n - 1) + 2 = (4n - 1) 2 Substituting n = 1, 2, 3, , we get the possible values of : = 3 2 , 7 2 , 11 2 , Answer: 3 2 , 7 2 , 11 2 ,

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