MHT CET 202622 AprilMorning Shift
- Exam
- MHT CET
- Year
- 2026
- Date
- 22 April
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Waves and Sound
MHT CET 2026 · 22 April · Morning Shift · Physics · Waves and Sound
A source of sound emitting a note of frequency n_0 is approaching a...
A source of sound emitting a note of frequency is approaching a stationary listener. If the frequency of the note heard by the listener , the velocity of the source is equal to
[ V = Velocity of sound in air]
[ V = Velocity of sound in air]
Options
- A
- B
- C
- D
Correct answer
B.
Step-by-step solution
Using the Doppler effect formula for a source approaching a stationary listener:
the given values,n' = 3n_03n_0 = n_0 \left( \dfrac{V}{V - V_s} \right)3 = \dfrac{V}{V - V_s}3V - 3V_s = V2V = 3V_sV_s = \dfrac{2V}{3}\dfrac{2V}{3}
the given values,n' = 3n_03n_0 = n_0 \left( \dfrac{V}{V - V_s} \right)3 = \dfrac{V}{V - V_s}3V - 3V_s = V2V = 3V_sV_s = \dfrac{2V}{3}\dfrac{2V}{3}