K_ s p of CaSO_4 · 5 H_2 O is 9 × 10^ -6 , find the volume for 1 ~g...

$$\begin{aligned}& \mathrm{CaSO}_{4(s)} \rightleftharpoons \mathrm{Ca}^{2+}{ }_{(a q)}+\mathrm{SO}_{4}{ }^{2-}{ }_{(a q)} \\ & S \\ & K_{s p}=S^2=9 \times10^{-6} \\ & S=3 \times10^{-3} \mathrm{ mol} \mathrm{ L}^{-1} \end{aligned}$$Solubility$in$\mathrm{g}$litre ^{-1}=$ molecular mass \times$S$=136 \times3 \times10^{-3}=408 \times10^{-3} \mathrm{ g} \mathrm{ L}^{-1}408 \times10^{-3} \mathrm{ g}$of$\mathrm{CaSO}_4 present in 1 litre 1 \mathrm{ g} of \mathrm{CaSO}_4 present is \frac{1}{408 \times 10^{-3}}=2.45$ litre