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AIIMS 2009
Exam
AIIMS
Year
2009
Subject
Chemistry
Chapter
Ionic Equilibrium

AIIMS 2009 · Chemistry · Ionic Equilibrium

pH of a 0.01 M solution (K_a=6.6 × 10^ -4 )

pH\mathrm{pH} of a 0.01M0.01 \mathrm{M} solution (Ka=6.6×10−4)\left(K_a=6.6 \times 10^{-4}\right)

Options

  1. A7.67.6
  2. B88
  3. C2.62.6
  4. D55

Correct answer

C. 2.62.6

Step-by-step solution

 α=KaC=6.6×10−40.01=6.6×10−2=0.257[H+]=Cα=0.01×0.257=2.57×10−3pH=3−log⁡2.5=2.60\begin{aligned} & \text{ } \alpha=\sqrt{\frac{K_a}{C}}=\sqrt{\frac{6.6 \times 10^{-4}}{0.01}}=\sqrt{6.6 \times 10^{-2}}=0.257 \\ & {\left[\mathrm{H}^{+}\right]=\mathrm{C} \alpha=0.01 \times 0.257=2.57 \times 10^{-3}} \\ & \mathrm{pH}=3-\log 2.5=2.60\end{aligned}
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