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AIIMS 2005
Exam
AIIMS
Year
2005
Subject
Chemistry
Chapter
Ionic Equilibrium

AIIMS 2005 · Chemistry · Ionic Equilibrium

When 10 ~mL of 0.1 M acetic acid (p K_a=5.0) is titrated against 10...

When 10 mL10 \mathrm{~mL} of 0.1M0.1 \mathrm{M} acetic acid (pKa=5.0)\left(\mathrm{p} K_a=5.0\right) is titrated against 10 mL10 \mathrm{~mL} of 0.1M0.1 \mathrm{M} ammonia solution ( pKb=5.0\mathrm{p} K_b=5.0 ), the equivalence point occurs at pH\mathrm{pH}

Options

  1. A5.0
  2. B6.0
  3. C7.0
  4. D9.0

Correct answer

C. 7.0

Step-by-step solution

:pKa=−log⁡Ka,pKb=−log⁡Kb: \mathrm{p} K_a=-\log K_a, \mathrm{p} K_b=-\log K_bpH=−12[log⁡Ka+log⁡Kw−log⁡Kb]=−12[5log⁡(1×10−14)−(5)]=−12[5−14−5]=−12(−14)=7\begin{aligned}\mathrm{pH}& =-\frac{1}{2}\left[\log K_a+\log K_w-\log K_b\right] \\ & =-\frac{1}{2}\left[5 \log \left(1 \times10^{-14}\right)-(5)\right] \\ & =-\frac{1}{2}[5-14-5]=-\frac{1}{2}(-14)=7 \end{aligned}
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