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NDA 2012
Exam
NDA
Year
2012
Subject
Mathematics
Chapter
Area Under Curves

NDA 2012 · Mathematics · Area Under Curves

What is the area of the portion of the curve y= x , lying between...

What is the area of the portion of the curve y=sin⁡xy=\sin x, lying between x=0,y=0x=0, y=0 and x=2πx=2 \pi ?

Options

  1. A1 square unit
  2. B2 square units
  3. C4 square units
  4. D8 square units

Correct answer

C. 4 square units

Step-by-step solution

 Area =2∫0πsin⁡xdx=2[−cos⁡x]0π=−2(−1−1)=4\begin{aligned} \text{ Area } & =2 \int_0^\pi \sin x d x=2[-\cos x]_0^\pi \\ & =-2(-1-1)=4\end{aligned}
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