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NDA 2010
Exam
NDA
Year
2010
Subject
Mathematics
Chapter
Area Under Curves

NDA 2010 · Mathematics · Area Under Curves

What is the area enclosed between the curves y^2=12 x and the lines...

What is the area enclosed between the curves y2=12xy^2=12 x and the lines x=0x=0 and y=6y=6 ?

Options

  1. A2 square units
  2. B4 square units
  3. C6 square units
  4. D8 square units

Correct answer

C. 6 square units

Step-by-step solution

A=∫06y212dy=112[y33]06=112×3×(6)3=6 sq. units \begin{aligned} & \mathrm{A}=\int_0^6 \frac{y^2}{1^2} d y=\frac{1}{12}\left[\frac{y^3}{3}\right]_0^6 \\ & =\frac{1}{12 \times 3} \times(6)^3=6 \text{ sq. units }\end{aligned}$$
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