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NDA 2022
Exam
NDA
Year
2022
Subject
Mathematics
Chapter
Differential Equations

NDA 2022 · Mathematics · Differential Equations

What is the degree of the differential equation 1+((d y)/(d...

What is the degree of the differential equation 1+(dydx)2=(d2ydx2)43?1+\left(\frac{d y}{d x}\right)^2=\left(\frac{d^2 y}{d x^2}\right)^{\frac{4}{3}} ?

Options

  1. A43\frac{4}{3}
  2. B2
  3. C3
  4. D4

Correct answer

D. 4

Step-by-step solution

1+(dydx)2=(d2ydx2)4/3[1+(dydx)2]3=(d2ydx2)4\begin{aligned} & 1+\left(\frac{d y}{d x}\right)^2=\left(\frac{d^2 y}{d x^2}\right)^{4 / 3} \\ & {\left[1+\left(\frac{d y}{d x}\right)^2\right]^3=\left(\frac{d^2 y}{d x^2}\right)^4}\end{aligned}\thereforeDegreeDegree=4$
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