If y= ⁻¹ ( 2 x 1+x^2 ) , then d y d x is equal to

Step-by-step solution

y= ⁻¹ ( 2 x 1+x^2 ) Put x = . = ⁻¹ x y= ⁻¹ ( 2 (1+ ^2 ) )= ⁻¹( 2 ) aligned & = ⁻¹ ( ( 2 -2 ) ) & = 2 -2 & dy dx = d dx ( 2 -2 ) aligned aligned & = d d x ( 2 -2 ⁻¹ x ) & d y d x = -2 1+x^2 , when |x| 1 aligned