What is the probability that the roots of the equation x^2+x+n=0 are real, where n N and n 4 ?

Step-by-step solution

A quadratic equation has only two roots. Here, x^2+x+n=0 and n N where n 4 n=1,2,3 Three equations are possible. Thus, Total number of Roots, n=6 For equation x^2+x+n=0 ; D =1-4 n D 0 when n=1,2 and 3 Equation will give complex roots not real. Thus, favourable number of roots, r=0 Hence, probability = r n = 0 6 =0