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NDA2011MathematicsQuadratic EquationActual

What are the roots of the equation 2(y+2)^2-5(y+2)=12 ?

Options

  1. A-7 / 2,2
  2. B-3 / 2,4
  3. C-5 / 3,3
  4. D3 / 2,4

Correct answer

A. -7 / 2,2

Step-by-step solution

Let y+2=x , equation can be written as array r 2 x^2-5 x-12=0 2 x^2-8 x+3 x-12=0 2 x(x-4)+3(x-4)=0 (x-4)(2 x+3)=0 array

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