NDA2025MathematicsStatisticsActual
Consider the following for the two (02) items that follow: The sum and the sum of squares of the observations corresponding to length X (in cm) and weight Y (in gm) of 50 tropical tubers are given as X = 200 , Y = 250 , X^2 = 900 and Y^2 = 1400 . Which one of the following statements is correct?
Options
- ACoefficient of variation of X is strictly more than coefficient of variation of Y .
- BCoefficient of variation of X is strictly less than coefficient of variation of Y .
- CCoefficient of variation of X is same as coefficient of variation of Y .
- DCoefficient of variation cannot be determined from the given data.
Correct answer
A. Coefficient of variation of X is strictly more than coefficient of variation of Y .
Step-by-step solution
Mean of X , X = X n = 200 50 = 4 Mean of Y , Y = Y n = 250 50 = 5 Variance of X , _X^2 = X^2 n - ( X )^2 = 900 50 - 4^2 = 18 - 16 = 2 Standard deviation of X , _X = 2 Variance of Y , _Y^2 = Y^2 n - ( Y )^2 = 1400 50 - 5^2 = 28 - 25 = 3 Standard deviation of Y , _Y = 3 Coefficient of variation of X , CV_X = _X X 100 = 2 4 100 = 25 2 35.35 % Coefficient of variation of Y , CV_Y = _Y Y 100 = 3 5 100 = 20 3 34.64 % Since 35.35 % > 34.64 % , the coefficient of variation of X is strictly more than the coefficient of vari