How many moles of lead (II) chloride will be formed from a reaction between 6.5 ~g of PbO and 3.2 ~g of HCl ?

Step-by-step solution

Key Idea : The reagent which is present in smaller quantity is called the limiting reagent and the moles of product depends on it and number of moles = weight molecular weight array ccc PbO & 2 HCl & PbCl ₂+ H ₂ O 207.2+16 & 2(35.5+1) & 207.2+71 =223.2 & =73 & =278.2 array Here, 1 mole of PbO reacts with 2 moles of HCl , thus PbO is the limiting reagent 223.2 ~g PbO gives PbCl ₂=278.2 ~g 6.5 ~g PbO will give PbCl ₂ aligned & = 278.2 223.2 6.5 ~g & = 278.2 6.5 223.2 278.2 ~mol & =0.029 ~mol aligned