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NEET 2009
Exam
NEET
Year
2009
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

NEET 2009 · Chemistry · Carboxylic Acid Derivatives

Consider the following reaction, Phenol Zn dust X Anhydrous AlCl_3...

Consider the following reaction, Phenol \stackrel{\mathrm{Zn} \text{ dust }}{\longrightarrow} \mathrm{X} \underset{\text{ Anhydrous } \mathrm{AlCl}_3}{\stackrel{\mathrm{CH}_3 \mathrm{Cl}}{\longrightarrow}} \mathrm{Y} \stackrel{ Alkaline KMnO\begin{array}{l}\text{ Alkaline } \\ \mathrm{KMnO}\end{array}$}{\longrightarrow}\mathrm{Z} , the product, ZZ, is$Consider the following reaction, Phenol Zn dust X Anhydrous AlCl_3 CH_3 Cl Y array l Alkaline KMnO array Z , the

Options

  1. Atoluene
  2. Bbenzaldehyde
  3. Cbenzoic acid
  4. Dbenzene

Correct answer

C. benzoic acid

Step-by-step solution

Key Idea (i) ZnZ n dust converts −OH-\mathrm{OH} group into- H\mathrm{H}. (ii) Reaction with CH3Cl\mathrm{CH}_3 \mathrm{Cl} in presence of anthy. AlCl3\mathrm{AlCl}_3 is called Friedel-Craft's alkylation. (iii) Alkaline KMnO4\mathrm{KMnO}_4 converts complete carbon chain which is directly attached with benzene ring, into - COOH\mathrm{COOH} group. Consider the following reaction, Phenol Zn dust X Anhydrous AlCl_3 CH_3 Cl Y array l Alkaline KMnO array Z , the
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