NEET2012ChemistryChemical KineticsActual
In a reaction, A+B Product, rate is doubled when the concentration of B is doubled, and rate increases by a factor of 8 when the concentrations of both the reactants (A and B ) are doubled. Rate law for the reaction can be written as
Options
- ARate =k[A][B]^2
- BRate =k[A]^2[B]^2
- CRate =k[A][B]
- DRate =k[A]^2[B]
Correct answer
D. Rate =k[A]^2[B]
Step-by-step solution
Let the order of reaction with respect to A and B is x and y respectively. So, the rate law can be given as R=k[A]^x[B]^y When the concentration of only B is doubled, the rate is doubled, so R₁=k[A]^x[2 B]^y=2 R If concentrations of both the reactants A and B are doubled, the rate increases by a factor of 8 , so aligned R^ =k[2 A]^x[2 B]^y & =8 R k 2^x 2^y[A]^x[B]^y & =8 R aligned From Eq. (i) and (ii), we get array rlrl & & 2 R R & = [A]^x[2 B]^y [A]^x[B]^y & & =2^y & y & =1 array From Eq. (i) and (iv), we get 8 R