In a zero order reaction for every 10^ rise of temperature, the rate is doubled. If the temperature is increased from 10^ C to 100^ C , the rate of the reaction will become

Step-by-step solution

For 10^ rise in temperature, n=1 so rate =2^n=2^1=2 When temperature is increased from 10^ C to 100^ C , change in temperature =100-10=90^ C , i.e., n=9 So, rate =2^9=512 times Alternate method With every 10^ rise in temperature, rate becomes double, so r^ r =2^ ( 100-10 10 ) =2^9=512 times.