If first ionization enthalpies of element X and Y are 419 ~kJ ~mol^ -1 and 590 ~kJ ~mol^ -1 , respectively and second ionization enthalpies of X and Y are 3069 kJ mol^ -1 and 1145 ~kJ ~mol^ -1 , respectively. Then

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Correct answer: A. X is an alkali metal and Y is an alkaline earth metal.

The highest jump ion successive ionisation energy indicates a stable noble gas configuration. If first ionization enthalpies of element X and Y are 419 ~kJ ~mol^ -1 and 590 ~kJ ~mol^ -1 , respectively and second

If first ionization enthalpies of element X and Y are 419 ~kJ ~mol^ -1 and 590 ~kJ ~mol^ -1 , respectively and second

The highest jump is observed in the

\mathrm{IE}_1 \& \mathrm{IE}_2

. It shows the attainment of stable noble gas configuration of

X

after losing one electron. Hence,

\mathrm{X}

is an alkali metal. The

\mathrm{IE}_1

of

Y

is

+590 \mathrm{~kJ} \mathrm{~mol}^{-1}

which is greater than

\mathrm{IE}_1

of

X

due to

n s^2

configuration.

\therefore \quad X=

Alkali metal and

Y=

Alkaline Earth metal

If first ionization enthalpies of element X and Y are 419 ~kJ ~mol^...

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