If first ionization enthalpies of element X and Y are 419 ~kJ ~mol ⁻¹ and 590 ~kJ ~mol ⁻¹ , respectively and second ionization enthalpies of X and Y are 3069 kJ mol ⁻¹ and 1145 ~kJ ~mol ⁻¹ , respectively. Then correct statement is :

Question

Quantrex Academy · Accepted Answer

Correct answer: A. X is an alkali metal and Y is an alkaline earth metal.

The highest jump ion successive ionisation energy indicates a stable noble gas configuration. The highest jump is observed in the IE ₁ & IE ₂ . It shows the attainment of stable noble gas configuration of X after losing one electron. Hence, X is an alkali metal. The IE ₁ of Y is +590 ~kJ ~mol ⁻¹ which is greater than IE ₁ of X due to n s^2 configuration. X= Alkali metal and Y= Alkaline Earth metal

If first ionization enthalpies of element X and Y are 419 ~kJ ~mol ⁻¹ and 590 ~kJ ~mol ⁻¹ , respectively and second ionization enthalpies of X and Y are 3069 kJ mol ⁻¹ and 1145 ~kJ ~mol ⁻¹ , respectively. Then correct statement is :

Options

Correct answer

Step-by-step solution

More from Classification of Elements and Periodicity in Properties