NEET2016ChemistryClassification of Elements and Periodicity in PropertiesActual
In which of the following options the order of arrangement does not agree with the variation of property indicated against it?
Options
- AA l 3 + < M g 2 + < N a + < F - (increasing ionic size)
- BB < C < N < O (increasing first ionization enthalpy)
- CI < B r < F < Cl (increasing electron gain enthalpy)
- DL i < N a < K < R b (increasing metallic radius)
Correct answer
B. B < C < N < O (increasing first ionization enthalpy)
Step-by-step solution
N is having n s 2   n p 3 (Half-filled configuration) which is extra stable electronic configuration, so high amount of energy will be required to remove outermost electron. Hence, N has high IP than O which is having n s 2   n p 4 electronic configuration.