In which of the following options the order of arrangement does not...

In which of the following options the order of arrangement does not agree with the variation of property indicated against it?

Options

A $A{l}^{3 +} < M{g}^{2 +} < N{a}^{+} < {F}^{-}$ (increasing ionic size)
B $B < C < N < O$ (increasing first ionization enthalpy)
C $I <Br < F<Cl$ (increasing electron gain enthalpy)
D $Li < Na < K < Rb$ (increasing metallic radius)

Correct answer

B. $B < C < N < O$ (increasing first ionization enthalpy)

Step-by-step solution

N is having

n{s}^{2}n{p}^{3}

(Half-filled configuration) which is extra stable electronic configuration, so high amount of energy will be required to remove outermost electron. Hence,

N

has high IP than O which is having

n{s}^{2}n{p}^{4}

electronic configuration.

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