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NEET2020ChemistryIonic EquilibriumActual

Find out the solubility of Ni OH 2 in 0.1   M   NaOH . Given that the ionic product of Ni OH 2 is 2 × 10 – 15 .

Options

  1. A2 × 10 – 8   M
  2. B1 × 10 – 13  M
  3. C1 × 10 8  M
  4. D2 × 10 – 13   M

Correct answer

D. 2 × 10 – 13   M

Step-by-step solution

α = 1 for NaOH NaOH ( aq ) → Na + 0 .1 M aq + OH − 0 .1 M aq Ni ( OH ) 2 s ⇌ Ni + 2 s ' aq + 2 OH − 0 .1 + 2 s ' aq Ionic product = s ' 0 .1 + 2 s ' 2 2 × 10 − 15 = s ' ( 0 . 1 ) 2 s ' = 2 × 10 − 13   M

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