Find out the solubility of Ni (OH) _ 2 in 0.1MNaOH . Given that the...

$\alpha = 1$ for $NaOH$

${NaOH}_{( aq )} \to \mathop{{Na}^{+}}_{0 .1 M}\left(aq\right) + \mathop{{OH}^{-}}_{0 .1 M}\left(aq\right)$

$Ni{( OH )}_{2}\left(s\right) ⇌ \mathop{{Ni}^{+ 2}}_{{s}^{'}}\left(aq\right) + \mathop{2{OH}^{-}}_{0 .1 + 2{s}^{'}}\left(aq\right)$

Ionic product $= \left({s}^{'}\right){\left(0 .1 + 2{s}^{'}\right)}^{2}$

$2 \times {10}^{- 15} = {s}^{'}{( 0 . 1 )}^{2}$

${s}^{'} = 2 \times {10}^{- 13}M$