The percentage of pyridine C 5 H 5 N that forms pyridinium ion C 5 H 5 N + H in a 0 . 10   M aqueous pyridine solution K b   for   C 5 H 5 N = 1 .7 × 10 - 9 is

Step-by-step solution

C 5 H 5 N + H 2 O ⇌ C 5 H 5 N ⊕ H + OH ⊖ t = 0 C t = eq C 1 - α C α C α ∴ K b = C α 2 1 - α ≈ C α 2 ∴ α = K b C = 1.7 × 10 - 9 0.1 = 1.3 × 1 0 - 4 ∴ %   α = 1.3 × 10 - 4 × 100 = 0.013 %