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NEET 2013
Exam
NEET
Year
2013
Subject
Chemistry
Chapter
Ionic Equilibrium

NEET 2013 · Chemistry · Ionic Equilibrium

The dissociation constant of a weak acid is 1 × 10^ -4 . In order...

The dissociation constant of a weak acid is 1×10−41 \times 10^{-4}. In order to prepare a buffer solution with a pH =5=5, the [Salt]/ [Acid] ratio should be:

Options

  1. A4:54: 5
  2. B10:110: 1
  3. C5:45: 4
  4. D1:101: 10

Correct answer

B. 10:110: 1

Step-by-step solution

pH=pKa+log⁡[ Salt ] Acid \mathrm{pH}=\mathrm{pK}_a+\log \frac{[\text{ Salt }]}{\text{ Acid }} \begin{aligned} & 5=\log \left[1 \times 10^{-4}\right]+\log \frac{[\text{ Salt }]}{[\text{ Acid }]} \\ & 5=4+\log \frac{[\text{ Salt }]}{[\text{ Acid }]} \\ & \frac{[\text{ Salt }]}{[\text{ Acid }]}=10: 1 \end{aligned}
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