pH of a saturated solution of Ba ( OH )₂ is 12. The value of solubility product K_ sp of Ba ( OH )₂ is

Step-by-step solution

Given, pH of Ba ( OH )₂=12 aligned pOH & =14- pH & =14-12=2 aligned We know that, aligned pOH & =- [ OH ⁻ ] 2 & =- [ OH ⁻ ] [ OH ⁻ ] & = antilog (-2) [ OH ⁻ ] & =1 10⁻² aligned Ba ( OH )₂ dissolves in water as aligned & Ba ( OH )₂(s) Ba _s²⁺+2 OH ₂⁻ & s ~mol ~L ⁻¹ & [ OH ⁻ ]=2 s=1 10⁻² & [ Ba ²⁺ ] = [ OH ⁻ ] 2 = 1 10⁻² 2 & K_ sp = [ Ba ²⁺ ] [ OH ⁻ ]^2 aligned aligned & = ( 1 10⁻² 2 ) (1 10⁻² )^2 & =0.5 10⁻⁶=5 10⁻⁷ aligned