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NEET 2022

Exam: NEET
Year: 2022
Subject: Chemistry
Chapter: p Block Elements (Group 13 & 14)

NEET 2022 · Chemistry · p Block Elements (Group 13 & 14)

Na_2 B_4 O_7 heat X+NaBO_2 in the above reaction the product " X "...

\mathrm{Na}_2 \mathrm{ B}_4 \mathrm{O}_7 \stackrel{\text{ heat }}{\longrightarrow} \mathrm{X}+\mathrm{NaBO}_2 in the above reaction the product "

\mathrm{X}

" is :

Options

A $\mathrm{H}_3 \mathrm{BO}_3$
B $\mathrm{B}_2 \mathrm{O}_3$
C $\mathrm{Na}_2 \mathrm{~B}_2 \mathrm{O}_5$
D $\mathrm{NaB}_3 \mathrm{O}_5$

Correct answer

B. $\mathrm{B}_2 \mathrm{O}_3$

Step-by-step solution

\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O} \underset{-10 \mathrm{H}_2 \mathrm{O}}{\stackrel{\Delta}{\longrightarrow}} \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7

\begin{array}{r} \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \stackrel{\Delta}{\longrightarrow} 2 \mathrm{NaBO}_2+\mathrm{B}_2 \mathrm{O}_3 \\ (\mathrm{X}) \end{array}

\mathrm{X}=

Boric anhydride

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