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NEET2022Chemistryp Block Elements (Group 13 & 14)Actual

Na ₂ ~B ₄ O ₇ heat X + NaBO ₂ in the above reaction the product " X " is :

Options

  1. AH ₃ BO ₃
  2. BB ₂ O ₃
  3. CNa ₂ ~B ₂ O ₅
  4. DNaB ₃ O ₅

Correct answer

B. B ₂ O ₃

Step-by-step solution

Na ₂ ~B ₄ O ₇ 10 H ₂ O -10 H ₂ O Na ₂ ~B ₄ O ₇ array r Na ₂ ~B ₄ O ₇ 2 NaBO ₂+ B ₂ O ₃ ( X ) array X = Boric anhydride

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