NEET 2026
- Exam
- NEET
- Year
- 2026
- Subject
- Chemistry
- Chapter
- p Block Elements (Group 13 & 14)
NEET 2026 · Chemistry · p Block Elements (Group 13 & 14)
Identify the incorrect statement from the following :
Identify the incorrect statement from the following :
Options
- ACarbon has the ability to form - multiple bond with itself.
- B is a monomer when and a dimer when .
- CThe order of catenation property of Group 14 elements is .
- DOxygen exhibits only oxidation state.
Correct answer
D. Oxygen exhibits only oxidation state.
Step-by-step solution
Carbon has a strong tendency to form - multiple bonds with itself, such as in alkenes and alkynes. Thus, the first statement is correct.
exists as a monomer because boron cannot expand its octet to form a dimer, whereas exists as a dimer () to complete its octet. Thus, the second statement is correct.
The catenation property depends on the element-element bond strength. The bond enthalpy decreases down the group, so the order of catenation is . Thus, the third statement is correct.
Oxygen exhibits a oxidation state in most of its compounds, but it also exhibits a oxidation state in peroxides (e.g., ), a oxidation state in superoxides (e.g., ), and positive oxidation states when bonded to fluorine (e.g., in and in ). Thus, the fourth statement is incorrect.
Answer: Oxygen exhibits only oxidation state.
exists as a monomer because boron cannot expand its octet to form a dimer, whereas exists as a dimer () to complete its octet. Thus, the second statement is correct.
The catenation property depends on the element-element bond strength. The bond enthalpy decreases down the group, so the order of catenation is . Thus, the third statement is correct.
Oxygen exhibits a oxidation state in most of its compounds, but it also exhibits a oxidation state in peroxides (e.g., ), a oxidation state in superoxides (e.g., ), and positive oxidation states when bonded to fluorine (e.g., in and in ). Thus, the fourth statement is incorrect.
Answer: Oxygen exhibits only oxidation state.